What is the integral from-2 to-1 of (3x^2-x-1) ?

The integral from-2 to-1 of (3x^2-x-1) is 15/2

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integral from-2 to-1 of (3x^2-x-1)

\int_{- 2}^{- 1} (3 x^{2} - x - 1) d x

\frac{15}{2}

Decimal

7.5

Solution steps

\int_{- 2}^{- 1} 3 x^{2} - x - 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{- 1} 3 x^{2} d x - \int_{- 2}^{- 1} x d x - \int_{- 2}^{- 1} 1 d x

\int_{- 2}^{- 1} 3 x^{2} d x = 7

\int_{- 2}^{- 1} x d x = - \frac{3}{2}

\int_{- 2}^{- 1} 1 d x = 1

= 7 - (- \frac{3}{2}) - 1

Simplify

7 - (- \frac{3}{2}) - 1 : \frac{15}{2}

= \frac{15}{2}

What is the integral from-2 to-1 of (3x^2-x-1) ?
The integral from-2 to-1 of (3x^2-x-1) is 15/2