integral from 2 to 4 of ln(x+1)

Lösung

\int_{2}^{4} ln (x + 1) d x

5 ln (5) - 2 - 3 ln (3)

Dezimale

2.75135 \dots

Schritte zur Lösung

\int_{2}^{4} ln (x + 1) d x

Wende U-Substitution an

= \int_{3}^{5} ln (u) d u

Wende die partielle Integration an

= [u ln (u) - \int 1 d u]_{3}^{5}

\int 1 d u = u

= [u ln (u) - u]_{3}^{5}

Berechne die Grenzen:

5 ln (5) - 2 - 3 ln (3)

= 5 ln (5) - 2 - 3 ln (3)

\int_{- 1}^{0} \frac{1}{x ^{2} + 2 x + 2} d x

\int_{1}^{3} \frac{1}{4 x - x ^{2}} d x

\int_{0}^{\frac{π}{2}} ∣ sin (x) ∣ d x

\int_{1}^{2} ln (3 x) - ln (x) d x

\int_{0}^{2} (x^{3} + 3 x - 1) d x