y^'=(e^{x-y})/(e^x+1)

Lösung

y^{^{'}} = \frac{e ^{x - y}}{e ^{x} + 1}

y = ln (ln (e^{x} + 1) + c_{1})

Schritte zur Lösung

y^{'} (x) = \frac{e ^{x - y}}{e ^{x} + 1}

Solve separable ODE:

y = ln (ln (e^{x} + 1) + c_{1})

y = ln (ln (e^{x} + 1) + c_{1})

\frac{d ^{2} y}{d x ^{2}} - 5 \frac{d y}{d x} + k y = 0

n = 1 \sum \infty \frac{3 ^{n}}{n 2 ^{n}}

\frac{\partial}{\partial y} (arctan (\frac{y}{x}))

y^{^{''}} + 18 y^{^{'}} + 97 y = 0

\frac{\partial}{\partial x} (arcsin (\frac{y}{( x ^{2} + y ^{2} ) ^{\frac{1}{2}}}))