integral from 2 to 4 of x^2+1

Lösung

\int_{2}^{4} x^{2} + 1 d x

\frac{62}{3}

Dezimale

20.66666 \dots

Schritte zur Lösung

\int_{2}^{4} x^{2} + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} x^{2} d x + \int_{2}^{4} 1 d x

\int_{2}^{4} x^{2} d x = \frac{56}{3}

\int_{2}^{4} 1 d x = 2

= \frac{56}{3} + 2

Vereinfache

\frac{56}{3} + 2 : \frac{62}{3}

= \frac{62}{3}

\int_{- 2}^{1} x^{3} + x^{2} - 2 x d x

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