integral from 1 to 5 of 2/(x^2)

Lösung

\int_{1}^{5} \frac{2}{x ^{2}} d x

\frac{8}{5}

Dezimale

1.6

Schritte zur Lösung

\int_{1}^{5} \frac{2}{x ^{2}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{1}^{5} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= 2 [- \frac{1}{x}]_{1}^{5}

Berechne die Grenzen:

\frac{4}{5}

= 2 \cdot \frac{4}{5}

Vereinfache

= \frac{8}{5}

\int_{0}^{1} x (x - 1) (x - 2) d x

\int_{- 1}^{1} x (x^{2} + 4)^{3} d x

\int_{0}^{3} 3^{3 x} d x

\int_{2}^{5} π (x^{2} - \frac{1}{5} x^{4}) d x

\int_{0}^{\frac{1}{2}} arcsin^{2} (x) d x