integral from 0 to 3 of 5t-9

Lösung

\int_{0}^{3} 5 t - 9 d t

- \frac{9}{2}

Dezimale

- 4.5

Schritte zur Lösung

\int_{0}^{3} 5 t - 9 d t

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 5 t d t - \int_{0}^{3} 9 d t

\int_{0}^{3} 5 t d t = \frac{45}{2}

\int_{0}^{3} 9 d t = 27

= \frac{45}{2} - 27

Vereinfache

\frac{45}{2} - 27 : - \frac{9}{2}

= - \frac{9}{2}

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