integral from 1 to 4 of |x^2-3x+2|

Lösung

\int_{1}^{4} x^{2} - 3 x + 2 d x

\frac{29}{6}

Dezimale

4.83333 \dots

Schritte zur Lösung

\int_{1}^{4} x^{2} - 3 x + 2 d x

Entferne die Extremwerte

= \int_{1}^{2} - x^{2} + 3 x - 2 d x + \int_{2}^{4} x^{2} - 3 x + 2 d x

\int_{1}^{2} - x^{2} + 3 x - 2 d x = \frac{1}{6}

\int_{2}^{4} x^{2} - 3 x + 2 d x = \frac{14}{3}

= \frac{1}{6} + \frac{14}{3}

Vereinfache

\frac{1}{6} + \frac{14}{3} : \frac{29}{6}

= \frac{29}{6}

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