What is the integral from-x to x^2 of 8x-10y+2 ?

The integral from-x to x^2 of 8x-10y+2 is -5x^4+8x^3+15x^2+2x

integral from-x to x^2 of 8x-10y+2

\int_{- x}^{x^{2}} 8 x - 10 y + 2 d y

- 5 x^{4} + 8 x^{3} + 15 x^{2} + 2 x

Solution steps

\int_{- x}^{x^{2}} 8 x - 10 y + 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- x}^{x^{2}} 2 d y - \int_{- x}^{x^{2}} 10 y d y + \int_{- x}^{x^{2}} 8 x d y

\int_{- x}^{x^{2}} 2 d y = 2 x^{2} + 2 x

\int_{- x}^{x^{2}} 10 y d y = 5 (x^{4} - x^{2})

\int_{- x}^{x^{2}} 8 x d y = 8 x^{3} + 8 x^{2}

= 2 x^{2} + 2 x - 5 (x^{4} - x^{2}) + 8 x^{3} + 8 x^{2}

Simplify

2 x^{2} + 2 x - 5 (x^{4} - x^{2}) + 8 x^{3} + 8 x^{2} : - 5 x^{4} + 8 x^{3} + 15 x^{2} + 2 x

= - 5 x^{4} + 8 x^{3} + 15 x^{2} + 2 x

\int_{0}^{1} \frac{e ^{x} + 1}{e ^{x}} d x

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\int_{0}^{1} x (3 x^{2} - 1)^{5} d x

\int_{1}^{2} (\frac{x}{2} - \frac{9}{x}) d x

\int_{a}^{b} ∣ x - 3 ∣ d x

What is the integral from-x to x^2 of 8x-10y+2 ?
The integral from-x to x^2 of 8x-10y+2 is -5x^4+8x^3+15x^2+2x