integral from 0 to 3 of-2y^2+6y

解答

\int_{0}^{3} - 2 y^{2} + 6 y d y

9

求解步骤

\int_{0}^{3} - 2 y^{2} + 6 y d y

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{3} 2 y^{2} d y + \int_{0}^{3} 6 y d y

\int_{0}^{3} 2 y^{2} d y = 18

\int_{0}^{3} 6 y d y = 27

= - 18 + 27

化简

= 9

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