integral from pi/2 to pi of cos(x)sin(x)

Lösung

\int_{\frac{π}{2}}^{π} cos (x) sin (x) d x

- \frac{1}{2}

Dezimale

- 0.5

Schritte zur Lösung

\int_{\frac{π}{2}}^{π} cos (x) sin (x) d x

Wende U-Substitution an

= \int_{1}^{0} u d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} u d u

Wende die Potenzregel an

= - [\frac{u ^{2}}{2}]_{0}^{1}

Berechne die Grenzen:

\frac{1}{2}

= - \frac{1}{2}

\int_{0}^{2} \frac{2}{x ^{2} + 4} d x

\int_{1}^{12} 4 e^{0.1 t} d t

\int_{0}^{5} w 25 - w^{2} d w

\int_{0}^{1} e^{- 5 t} d t

\int_{1}^{4} x (2 - x) d x