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人気のある微分積分 >

integral from 0 to 1 of (2-x)

解

\int_{0}^{1} (2 - x) d x

解

\frac{3}{2}

+1

十進法表記

1.5

解答ステップ

\int_{0}^{1} 2 - x d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2 d x - \int_{0}^{1} x d x

\int_{0}^{1} 2 d x = 2

\int_{0}^{1} x d x = \frac{1}{2}

= 2 - \frac{1}{2}

簡素化

2 - \frac{1}{2} : \frac{3}{2}

= \frac{3}{2}

グラフ

人気の例

integral from 1 to 5 of 2x+7

\int_{1}^{5} 2 x + 7 d x

integral from 0 to 18pi of sin(x)

\int_{0}^{18 π} sin (x) d x

integral from 1 to 2 of (x-3)/(x^3+x^2)

\int_{1}^{2} \frac{x - 3}{x ^{3} + x ^{2}} d x

integral from 0 to t of u

\int_{0}^{t} u d u

integral from 0 to t of s

\int_{0}^{t} s d s