integral from 1 to 2 of (3x+2)

Lösung

\int_{1}^{2} (3 x + 2) d x

\frac{13}{2}

Dezimale

6.5

Schritte zur Lösung

\int_{1}^{2} 3 x + 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 3 x d x + \int_{1}^{2} 2 d x

\int_{1}^{2} 3 x d x = \frac{9}{2}

\int_{1}^{2} 2 d x = 2

= \frac{9}{2} + 2

Vereinfache

\frac{9}{2} + 2 : \frac{13}{2}

= \frac{13}{2}

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