integral from-1 to 0 of (-x-1)

解答

\int_{- 1}^{0} (- x - 1) d x

- \frac{1}{2}

十进制

- 0.5

求解步骤

\int_{- 1}^{0} - x - 1 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{- 1}^{0} x d x - \int_{- 1}^{0} 1 d x

\int_{- 1}^{0} x d x = - \frac{1}{2}

\int_{- 1}^{0} 1 d x = 1

= - (- \frac{1}{2}) - 1

化简

- (- \frac{1}{2}) - 1 : - \frac{1}{2}

= - \frac{1}{2}

\int_{0}^{\frac{x}{n}} n (1 - x)^{n - 1} d x

\int_{0}^{\frac{π}{2}} x cos (n x) d x

\int_{x^{4}}^{x^{5}} (2 t - 1)^{3} d t

\int_{- 4}^{- 3} x^{2} - (2 x + 15) d x

\int_{0}^{2} 2 x (x^{2} - 1)^{3} d x