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Popular Calculus >

integral from 0 to 4 of x^2-4

Solution

\int_{0}^{4} x^{2} - 4 d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{0}^{4} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 4 d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 4 d x = 16

= \frac{64}{3} - 16

Simplify

\frac{64}{3} - 16 : \frac{16}{3}

= \frac{16}{3}

Graph

Popular Examples

integral from 2 to 5 of 3^{5x}

\int_{2}^{5} 3^{5 x} d x

integral from-2 to-1 of 1/(x^2)

\int_{- 2}^{- 1} \frac{1}{x ^{2}} d x

integral from 0 to 1 of (-x+1)^2

\int_{0}^{1} (- x + 1)^{2} d x

integral from 0 to 1 of-x^2+x

\int_{0}^{1} - x^{2} + x d x

integral from 0 to 1 of (x^2+y^2)

\int_{0}^{1} (x^{2} + y^{2}) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of x^2-4 ?
The integral from 0 to 4 of x^2-4 is 16/3