What is the integral from-1 to 3 of (x^2) ?

The integral from-1 to 3 of (x^2) is 28/3

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integral from-1 to 3 of (x^2)

\int_{- 1}^{3} (x^{2}) d x

\frac{28}{3}

Decimal

9.33333 \dots

Solution steps

\int_{- 1}^{3} x^{2} d x

Apply the Power Rule

= [\frac{x ^{3}}{3}]_{- 1}^{3}

Compute the boundaries:

\frac{28}{3}

= \frac{28}{3}

\int_{0}^{2} \frac{1}{25 - x ^{2}} d x

\int_{\frac{π}{5}}^{π} ∣ cos (x) ∣ d x

\int_{0}^{1} \frac{x}{x ^{2} + 2} d x

\int_{- 1}^{0} (x^{5}) x^{3} + 1 d x

\int_{0}^{1} \frac{x ^{3}}{2} d x

What is the integral from-1 to 3 of (x^2) ?
The integral from-1 to 3 of (x^2) is 28/3