What is the derivative of 1+5sin(x) ?

The derivative of 1+5sin(x) is 5cos(x)

What is the first derivative of 1+5sin(x) ?

The first derivative of 1+5sin(x) is 5cos(x)

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\frac{d}{d x} (1 + 5 sin (x))

5 cos (x)

Solution steps

\frac{d}{d x} (1 + 5 sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (5 sin (x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (5 sin (x)) = 5 cos (x)

= 0 + 5 cos (x)

Simplify

= 5 cos (x)

\frac{d}{d x} (e^{a x} cos (b x))

2 y^{^{'}} + 3 y = 0

d er i v a t i v e x \cdot 3 x^{2} + 5

a re a x^{2} - 2, x, - 2, 2

x \to - 4 lim (- x^{2} + 4 x - 9)

What is the derivative of 1+5sin(x) ?
The derivative of 1+5sin(x) is 5cos(x)
What is the first derivative of 1+5sin(x) ?
The first derivative of 1+5sin(x) is 5cos(x)