What is the integral from x to 2 of 1/2 ?

The integral from x to 2 of 1/2 is 1-x/2

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integral from x to 2 of 1/2

\int_{x}^{2} \frac{1}{2} d y

1 - \frac{x}{2}

Solution steps

\int_{x}^{2} \frac{1}{2} d y

Integral of a constant:

\int a d x = a x

= [\frac{1}{2} y]_{x}^{2}

Compute the boundaries:

1 - \frac{1}{2} x

= 1 - \frac{1}{2} x

Simplify

= 1 - \frac{x}{2}

\int_{1}^{2} 5^{5 x} d x

\int_{0}^{\frac{π}{3}} \frac{4 sin ( θ )}{1 - 4 cos ( θ )} d θ

\int_{1}^{2} x + 1 d x

\int_{- 7}^{7} x^{3} d x

\int_{1}^{3} r^{4} ln (r) d r

What is the integral from x to 2 of 1/2 ?
The integral from x to 2 of 1/2 is 1-x/2