What is the tangent of y=x^2+2,(-4,18) ?

The tangent of y=x^2+2,(-4,18) is y=-8x-14

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tangent of y=x^2+2,(-4,18)

tangent of

y = x^{2} + 2, (- 4, 18)

y = - 8 x - 14

Solution steps

Find the slope of

y = x^{2} + 2 : \frac{d y}{d x} = 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 8

Find the line with slope m=

- 8

and passing through

(- 4, 18) : y = - 8 x - 14

y = - 8 x - 14

a re a y = 7 x, y = \frac{7}{4} x, y = 78 - x^{2}

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What is the tangent of y=x^2+2,(-4,18) ?
The tangent of y=x^2+2,(-4,18) is y=-8x-14