integral from 0 to pi/4 of 9sec(θ)tan(θ)

Lösung

\int_{0}^{\frac{π}{4}} 9 sec (θ) tan (θ) d θ

9 (2 - 1)

Dezimale

3.72792 \dots

Schritte zur Lösung

\int_{0}^{\frac{π}{4}} 9 sec (θ) tan (θ) d θ

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 9 \cdot \int_{0}^{\frac{π}{4}} sec (θ) tan (θ) d θ

Wende U-Substitution an

= 9 \cdot \int_{1}^{2} 1 d u

Integral einer Konstanten :

\int a d x = a x

= 9 [1 \cdot u]_{1}^{2}

Vereinfache

= 9 [u]_{1}^{2}

Berechne die Grenzen:

2 - 1

= 9 (2 - 1)

\int_{- 2}^{2} 4 - x d x

\int_{0}^{π} cos (2 t) d t

\int_{0}^{2} 2 y - y^{2} d y

\int_{1}^{5} \frac{7}{x} d x

\int_{0}^{2} 15 x^{2} + 14 x - 8 d x