What is the integral from 0 to 2 of (2x) ?

The integral from 0 to 2 of (2x) is 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 2 of (2x)

\int_{0}^{2} (2 x) d x

4

Solution steps

\int_{0}^{2} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{2} x d x

Apply the Power Rule

= 2 [\frac{x ^{2}}{2}]_{0}^{2}

Compute the boundaries:

2

= 2 \cdot 2

Simplify

= 4

\int_{0}^{\frac{π}{2}} 4 sin (x) d x

\int_{1}^{32} x^{- \frac{7}{5}} d x

\int_{0}^{1} y e^{y^{2}} d y

\int_{0}^{1} x 3 - 2 x d x

\int_{1}^{2} t^{2} d t

What is the integral from 0 to 2 of (2x) ?
The integral from 0 to 2 of (2x) is 4