integral from 0 to 2 of x^2+x+1

Lösung

\int_{0}^{2} x^{2} + x + 1 d x

\frac{20}{3}

Dezimale

6.66666 \dots

Schritte zur Lösung

\int_{0}^{2} x^{2} + x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x + \int_{0}^{2} x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} x d x = 2

\int_{0}^{2} 1 d x = 2

= \frac{8}{3} + 2 + 2

Vereinfache

\frac{8}{3} + 2 + 2 : \frac{20}{3}

= \frac{20}{3}

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