integral from 1 to 3 of x^2-6x+5

Lösung

\int_{1}^{3} x^{2} - 6 x + 5 d x

- \frac{16}{3}

Dezimale

- 5.33333 \dots

Schritte zur Lösung

\int_{1}^{3} x^{2} - 6 x + 5 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x^{2} d x - \int_{1}^{3} 6 x d x + \int_{1}^{3} 5 d x

\int_{1}^{3} x^{2} d x = \frac{26}{3}

\int_{1}^{3} 6 x d x = 24

\int_{1}^{3} 5 d x = 10

= \frac{26}{3} - 24 + 10

Vereinfache

\frac{26}{3} - 24 + 10 : - \frac{16}{3}

= - \frac{16}{3}

\int_{2}^{3} x^{2} + x - 2 d x

\int_{- 2}^{2} 4^{\frac{x}{2}} d x

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