integral from 0 to 1 of x^2cos(x)

Lösung

\int_{0}^{1} x^{2} cos (x) d x

2 cos (1) - sin (1)

Dezimale

0.23913 \dots

Schritte zur Lösung

\int_{0}^{1} x^{2} cos (x) d x

Wende die partielle Integration an

= [x^{2} sin (x) - \int 2 x sin (x) d x]_{0}^{1}

\int 2 x sin (x) d x = 2 (- x cos (x) + sin (x))

= [x^{2} sin (x) - 2 (- x cos (x) + sin (x))]_{0}^{1}

Berechne die Grenzen:

2 cos (1) - sin (1)

= 2 cos (1) - sin (1)

\int_{0}^{1} (2 t + 1) e^{- s t} d t

\int_{0}^{3} 0 d x

\int_{0}^{15 π} sin (x) d x

\int_{0}^{3} 5^{2 x} d x

\int_{0}^{1} x \cdot e^{2 x} d x