integral from-8 to 0 of (y/8+sqrt(y+9))

Lösung

\int_{- 8}^{0} (\frac{y}{8} + y + 9) d y

\frac{40}{3}

Dezimale

13.33333 \dots

Schritte zur Lösung

\int_{- 8}^{0} \frac{y}{8} + y + 9 d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 8}^{0} \frac{y}{8} d y + \int_{- 8}^{0} y + 9 d y

\int_{- 8}^{0} \frac{y}{8} d y = - 4

\int_{- 8}^{0} y + 9 d y = \frac{52}{3}

= - 4 + \frac{52}{3}

Vereinfache

- 4 + \frac{52}{3} : \frac{40}{3}

= \frac{40}{3}

x \to \infty lim (x + 9)

\int \frac{1}{x ^{2} + 3 x + 3} d x

y^{''} (x) - 3 y^{'} (x) + 2 y = \frac{1}{1 + e ^{- x}}

x \to 0 lim (- arcsin (x))

\frac{d}{d x} (5 e^{x} + \frac{2}{3 x})