integral from 1 to t of 1/(x^2)

Lösung

\int_{1}^{t} \frac{1}{x ^{2}} d x

- \frac{1}{t} + 1

Schritte zur Lösung

\int_{1}^{t} \frac{1}{x ^{2}} d x

Wende die Potenzregel an

= [- \frac{1}{x}]_{1}^{t}

Berechne die Grenzen:

- \frac{1}{t} + 1

= - \frac{1}{t} + 1

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