What is the integral from 0 to 2pi of-4 ?

The integral from 0 to 2pi of-4 is -8pi

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 2pi of-4

\int_{0}^{2 π} - 4 d t

- 8 π

Decimal

- 25.13274 \dots

Solution steps

\int_{0}^{2 π} - 4 d t

Integral of a constant:

\int a d x = a x

= [(- 4) t]_{0}^{2 π}

Simplify

= [- 4 t]_{0}^{2 π}

Compute the boundaries:

- 8 π

= - 8 π

\int_{- 1}^{1} e^{x} - e^{- x} d x

\int_{- 7}^{7} ∣ x ∣ d x

\int_{- 2}^{0} x^{2} + x d x

\int_{- 5}^{2} \frac{x}{( x + 6 ) ^{\frac{2}{3}}} d x

\int_{1}^{\infty} ln (x^{2}) d x

What is the integral from 0 to 2pi of-4 ?
The integral from 0 to 2pi of-4 is -8pi