What is the integral of-7sin(x)+4cos(x) ?

The integral of-7sin(x)+4cos(x) is 7cos(x)+4sin(x)+C

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integral of-7sin(x)+4cos(x)

\int - 7 sin (x) + 4 cos (x) d x

7 cos (x) + 4 sin (x) + C

Solution steps

\int - 7 sin (x) + 4 cos (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int 7 sin (x) d x + \int 4 cos (x) d x

\int 7 sin (x) d x = - 7 cos (x)

\int 4 cos (x) d x = 4 sin (x)

= - (- 7 cos (x)) + 4 sin (x)

Simplify

= 7 cos (x) + 4 sin (x)

Add a constant to the solution

= 7 cos (x) + 4 sin (x) + C

\int tan^{3} (2 x) sec^{5} (2 x) d x

\frac{d}{d x} (e^{2 x} cos (4 x))

\int 6 x^{4} - 5 x^{3} + 5 x^{2} + C d x

x \to \infty lim (arctan (1 - x))

x \to 0 + lim (arctan (ln (x)))

What is the integral of-7sin(x)+4cos(x) ?
The integral of-7sin(x)+4cos(x) is 7cos(x)+4sin(x)+C