斜率 (1/2 ,7),(3,-3/2)

解答

斜率

(\frac{1}{2}, 7), (3, - \frac{3}{2})

m = - \frac{17}{5}

求解步骤

两点之间的斜率: 斜率

= \frac{y _{2} - y _{1}}{x _{2} - x _{1}}

(x_{1}, y_{1}) = (\frac{1}{2}, 7), (x_{2}, y_{2}) = (3, - \frac{3}{2})

m = \frac{- \frac{3}{2} - 7}{3 - \frac{1}{2}}

整理后得

m = - \frac{17}{5}

d er i v a t i v e f (t) = \frac{( t ^{2} - 4 t )}{t + 3}

\int \frac{2 x + 3}{x ^{2} + 3 x + 4} d x

x \to 0 + lim (x^{n})

\frac{\partial}{\partial x} (8 x e^{x^{2}} + y^{2})

x \to \infty lim (3 \frac{5 - 8 x}{x + 3})