What is the integral from 0 to x of y ?

The integral from 0 to x of y is (x^2)/2

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integral from 0 to x of y

\int_{0}^{x} y d y

\frac{x ^{2}}{2}

Solution steps

\int_{0}^{x} y d y

Apply the Power Rule

= [\frac{y ^{2}}{2}]_{0}^{x}

Compute the boundaries:

\frac{x ^{2}}{2}

= \frac{x ^{2}}{2}

\int_{0}^{1} (3 + x^{2})^{2} x d x

\int_{0}^{π} sin (θ) cos (θ) d θ

\int_{2}^{6} 1 d x

\int_{- 3}^{2} - 2 x d x

\int_{0}^{2 π} x sin (x) cos (x) d x

What is the integral from 0 to x of y ?
The integral from 0 to x of y is (x^2)/2