What is the integral from 1 to 4 of xsqrt(9+x^2) ?

The integral from 1 to 4 of xsqrt(9+x^2) is (125-10sqrt(10))/3

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integral from 1 to 4 of xsqrt(9+x^2)

\int_{1}^{4} x 9 + x^{2} d x

\frac{125 - 10 10}{3}

Decimal

31.12574 \dots

Solution steps

\int_{1}^{4} x 9 + x^{2} d x

Apply u-substitution

= \int_{10}^{5} u^{2} d u

Apply the Power Rule

= [\frac{u ^{3}}{3}]_{10}^{5}

Compute the boundaries:

\frac{125}{3} - \frac{10 10}{3}

= \frac{125}{3} - \frac{10 10}{3}

Simplify

= \frac{125 - 10 10}{3}

\int_{0}^{2} x^{3} e^{x^{4}} d x

\int_{0}^{3} x + 2 d x

\int_{- 2}^{0} 3 - x^{2} d x

\int_{0}^{\frac{π}{2}} cos (y) d y

\int_{4}^{9} \frac{1}{1 + x} d x

What is the integral from 1 to 4 of xsqrt(9+x^2) ?
The integral from 1 to 4 of xsqrt(9+x^2) is (125-10sqrt(10))/3