What is the integral from-e to-1 of 1/x ?

The integral from-e to-1 of 1/x is -1

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integral from-e to-1 of 1/x

\int_{- e}^{- 1} \frac{1}{x} d x

- 1

Solution steps

\int_{- e}^{- 1} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= [ln ∣ x ∣]_{- e}^{- 1}

Compute the boundaries:

- 1

= - 1

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