integral from 1 to 3 of (x+1)

Lösung

\int_{1}^{3} (x + 1) d x

6

Schritte zur Lösung

\int_{1}^{3} x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} x d x + \int_{1}^{3} 1 d x

\int_{1}^{3} x d x = 4

\int_{1}^{3} 1 d x = 2

= 4 + 2

Vereinfache

= 6

\int_{a}^{b} x^{3} d x

\int_{0}^{3} y^{2} d y

\int_{0}^{2} x^{2} e^{- 2 x} d x

\int_{0}^{4} (4 y - y^{2}) d y

\int_{- 1}^{1} x^{3} cos (x) d x