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人気のある微分積分 >

integral from 0 to ln(4) of 6e^{2x}

解

\int_{0}^{l n (4)} 6 e^{2 x} d x

解

45

解答ステップ

\int_{0}^{l n (4)} 6 e^{2 x} d x

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \int_{0}^{l n (4)} e^{2 x} d x

u置換積分法を適用する

= 6 \cdot \int_{0}^{4 l n (2)} e^{u} \frac{1}{2} d u

定数を除く:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 6 \cdot \frac{1}{2} \cdot \int_{0}^{4 l n (2)} e^{u} d u

共通積分を使用する:

\int e^{u} d u = e^{u}

= 6 \cdot \frac{1}{2} [e^{u}]_{0}^{4 l n (2)}

簡素化

6 \cdot \frac{1}{2} [e^{u}]_{0}^{4 l n (2)} : 3 [e^{u}]_{0}^{4 l n (2)}

= 3 [e^{u}]_{0}^{4 l n (2)}

限度を計算する:

15

= 3 \cdot 15

簡素化

= 45

グラフ

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