integral from 1 to 8 of (1+x^3)

Lösung

\int_{1}^{8} (1 + x^{3}) d x

\frac{4123}{4}

Dezimale

1030.75

Schritte zur Lösung

\int_{1}^{8} 1 + x^{3} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{8} 1 d x + \int_{1}^{8} x^{3} d x

\int_{1}^{8} 1 d x = 7

\int_{1}^{8} x^{3} d x = \frac{4095}{4}

= 7 + \frac{4095}{4}

Vereinfache

7 + \frac{4095}{4} : \frac{4123}{4}

= \frac{4123}{4}

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