What is the integral from 0 to 2 of-x^2 ?

The integral from 0 to 2 of-x^2 is -8/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 2 of-x^2

\int_{0}^{2} - x^{2} d x

- \frac{8}{3}

Decimal

- 2.66666 \dots

Solution steps

\int_{0}^{2} - x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{2} x^{2} d x

Apply the Power Rule

= - [\frac{x ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= - \frac{8}{3}

\int_{0}^{y} x (y^{2} - x^{2})^{\frac{3}{2}} d x

\int_{0}^{\frac{π}{2}} 4 sin (\frac{x}{2}) d x

\int_{0}^{y} 1 d x

\int_{0}^{π} x sin (\frac{x}{2}) d x

\int_{0}^{1} a + b x^{2} d x

What is the integral from 0 to 2 of-x^2 ?
The integral from 0 to 2 of-x^2 is -8/3