integral from 1 to 2 of ax^3+6/(x^2)

Lösung

\int_{1}^{2} a x^{3} + \frac{6}{x ^{2}} d x

\frac{15 a}{4} + 3

Schritte zur Lösung

\int_{1}^{2} a x^{3} + \frac{6}{x ^{2}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} a x^{3} d x + \int_{1}^{2} \frac{6}{x ^{2}} d x

\int_{1}^{2} a x^{3} d x = \frac{15 a}{4}

\int_{1}^{2} \frac{6}{x ^{2}} d x = 3

= \frac{15 a}{4} + 3

\int_{- \infty}^{0} \frac{1}{x} d x

\int_{- \frac{π}{2}}^{\frac{π}{2}} 1

\int_{1}^{0} x d x

\int_{2}^{6} (3 x + 4) d x

\int_{1}^{2} (3 x - 7) (x - 3) d x