integral from 1 to 3 of (2x-1)

Lösung

\int_{1}^{3} (2 x - 1) d x

6

Schritte zur Lösung

\int_{1}^{3} 2 x - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} 2 x d x - \int_{1}^{3} 1 d x

\int_{1}^{3} 2 x d x = 8

\int_{1}^{3} 1 d x = 2

= 8 - 2

Vereinfache

= 6

\int_{- 1}^{3} 2 x - x^{2} d x

\int_{0}^{π} sin (x) \cdot sin (n x) d x

\int_{0}^{1} - x + 1 d x

\int_{0}^{1} 4 x f (x^{2} + 1) d x

\int_{0}^{\frac{π}{2}} \frac{sin ( x )}{x} d x