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Popular Calculus >

integral from 0 to 9 of |x^2-4|

Solution

\int_{0}^{9} x^{2} - 4 d x

Solution

\frac{653}{3}

+1

Decimal

217.66666 \dots

Solution steps

\int_{0}^{9} x^{2} - 4 d x

Eliminate Absolutes

= \int_{0}^{2} - x^{2} + 4 d x + \int_{2}^{9} x^{2} - 4 d x

\int_{0}^{2} - x^{2} + 4 d x = \frac{16}{3}

\int_{2}^{9} x^{2} - 4 d x = \frac{637}{3}

= \frac{16}{3} + \frac{637}{3}

Simplify

\frac{16}{3} + \frac{637}{3} : \frac{653}{3}

= \frac{653}{3}

Graph

Popular Examples

integral from-2 to 3 of 2/(3x^2)

\int_{- 2}^{3} \frac{2}{3 x ^{2}} d x

integral from 0 to e of ((x^2-9)/(x+3))

\int_{0}^{e} (\frac{x ^{2} - 9}{x + 3}) d x

integral from-1 to 4 of 2

\int_{- 1}^{4} 2 d x

integral from 1 to 7 of t^2-2t-24

\int_{1}^{7} t^{2} - 2 t - 24 d t

integral from 0 to 1 of 3x^2e^{x^3}

\int_{0}^{1} 3 x^{2} e^{x^{3}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 9 of |x^2-4| ?
The integral from 0 to 9 of |x^2-4| is 653/3