What is the integral from-1 to 1 of t ?

The integral from-1 to 1 of t is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-1 to 1 of t

\int_{- 1}^{1} t d t

0

Solution steps

\int_{- 1}^{1} t d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

t :

Odd

= 0

\int_{- 3}^{0} (- x^{2} - 3 x) d x

\int_{0}^{π} (π - x) d x

\int_{- 1}^{0} \frac{1}{4 x ^{2} - 9} d x

\int_{1}^{e^{x}} 4 ln (t) d t

\int_{- 3}^{5} (4 x - 3)^{3} d x