What is the integral of cos(7x-9) ?

The integral of cos(7x-9) is 1/7 sin(7x-9)+C

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integral of cos(7x-9)

\int cos (7 x - 9) d x

\frac{1}{7} sin (7 x - 9) + C

Solution steps

\int cos (7 x - 9) d x

Apply u-substitution

= \int cos (u) \frac{1}{7} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{7} \cdot \int cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= \frac{1}{7} sin (u)

Substitute back

u = 7 x - 9

= \frac{1}{7} sin (7 x - 9)

Add a constant to the solution

= \frac{1}{7} sin (7 x - 9) + C

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What is the integral of cos(7x-9) ?
The integral of cos(7x-9) is 1/7 sin(7x-9)+C