What is the integral of x^2+2x-35 ?

The integral of x^2+2x-35 is (x^3)/3+x^2-35x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of x^2+2x-35

\int x^{2} + 2 x - 35 d x

\frac{x ^{3}}{3} + x^{2} - 35 x + C

Solution steps

\int x^{2} + 2 x - 35 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int 2 x d x - \int 35 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int 2 x d x = x^{2}

\int 35 d x = 35 x

= \frac{x ^{3}}{3} + x^{2} - 35 x

Add a constant to the solution

= \frac{x ^{3}}{3} + x^{2} - 35 x + C

\int 2 x - sec^{2} (x) d x

\int 27 sin^{3} (x) d x

\int - x sin^{2} (x) d x

\int (sinh (x) + x^{2}) d x

\int t 4 + 5 t d t

What is the integral of x^2+2x-35 ?
The integral of x^2+2x-35 is (x^3)/3+x^2-35x+C