What is the integral of (12x^8-x)/(x^3) ?

The integral of (12x^8-x)/(x^3) is 2x^6+1/x+C

integral of (12x^8-x)/(x^3)

\int \frac{12 x ^{8} - x}{x ^{3}} d x

2 x^{6} + \frac{1}{x} + C

Solution steps

\int \frac{12 x ^{8} - x}{x ^{3}} d x

Expand

\frac{12 x ^{8} - x}{x ^{3}} : 12 x^{5} - \frac{1}{x ^{2}}

= \int 12 x^{5} - \frac{1}{x ^{2}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 12 x^{5} d x - \int \frac{1}{x ^{2}} d x

\int 12 x^{5} d x = 2 x^{6}

\int \frac{1}{x ^{2}} d x = - \frac{1}{x}

= 2 x^{6} - (- \frac{1}{x})

Simplify

= 2 x^{6} + \frac{1}{x}

Add a constant to the solution

= 2 x^{6} + \frac{1}{x} + C

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What is the integral of (12x^8-x)/(x^3) ?
The integral of (12x^8-x)/(x^3) is 2x^6+1/x+C