What is the integral of (8x+3sin(x)) ?

The integral of (8x+3sin(x)) is 4x^2-3cos(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (8x+3sin(x))

\int (8 x + 3 sin (x)) d x

4 x^{2} - 3 cos (x) + C

Solution steps

\int 8 x + 3 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x d x + \int 3 sin (x) d x

\int 8 x d x = 4 x^{2}

\int 3 sin (x) d x = - 3 cos (x)

= 4 x^{2} - 3 cos (x)

Add a constant to the solution

= 4 x^{2} - 3 cos (x) + C

\int \frac{sin ( 2 x )}{1 + e ^{c o s^{2} (x)}} d x

\int \frac{- sec ^{2} ( x )}{5} d x

\int \frac{8 x}{x ^{2} + 4} d x

\int \frac{6 x}{x ^{2} + 3} d x

\int \frac{1}{5 - 16 x ^{2}} d x

What is the integral of (8x+3sin(x)) ?
The integral of (8x+3sin(x)) is 4x^2-3cos(x)+C