What is the integral of sin(x)cos(x)e^{sin^2(x+pi)} ?

The integral of sin(x)cos(x)e^{sin^2(x+pi)} is 1/2 e^{sin^2(x)}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of sin(x)cos(x)e^{sin^2(x+pi)}

\int sin (x) cos (x) e^{s i n^{2} (x + π)} d x

\frac{1}{2} e^{s i n^{2} (x)} + C

Solution steps

\int sin (x) cos (x) e^{s i n^{2} (x + π)} d x

Rewrite using trig identities

= \int e^{s i n^{2} (x)} sin (x) cos (x) d x

Apply u-substitution

= \int e^{u^{2}} u d u

Apply u-substitution

= \int \frac{e ^{v}}{2} d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int e^{v} d v

Use the common integral:

\int e^{v} d v = e^{v}

= \frac{1}{2} e^{v}

Substitute back

= \frac{1}{2} e^{s i n^{2} (x)}

Add a constant to the solution

= \frac{1}{2} e^{s i n^{2} (x)} + C

\int (sin (8 x)) d x

\int (e^{x} + 4^{(x + 2)}) d x

\int x + y + 1

\int \frac{x + 1}{3 x ^{2}} d x

\int \frac{arcsin ( z )}{1 - z ^{2}} d z

What is the integral of sin(x)cos(x)e^{sin^2(x+pi)} ?
The integral of sin(x)cos(x)e^{sin^2(x+pi)} is 1/2 e^{sin^2(x)}+C