integral of csch^2(θ)e^{coth(θ)}

解答

\int csch^{2} (θ) e^{c o t h (θ)} d θ

- e^{c o t h (θ)} + C

求解步骤

\int csch^{2} (θ) e^{c o t h (θ)} d θ

使用换元积分法

= \int - 1 d u

常数积分:

\int a d x = a x

= (- 1) u

u = e^{c o t h (θ)}

代回

= (- 1) e^{c o t h (θ)}

化简

= - e^{c o t h (θ)}

解答补常数

= - e^{c o t h (θ)} + C

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