What is the integral of (ln^9(z))/z ?

The integral of (ln^9(z))/z is (ln^{10}(z))/(10)+C

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integral of (ln^9(z))/z

\int \frac{ln ^{9} ( z )}{z} d z

\frac{ln ^{10} ( z )}{10} + C

Solution steps

\int \frac{ln ^{9} ( z )}{z} d z

Apply u-substitution

= \int u^{9} d u

Apply the Power Rule

= \frac{u ^{10}}{10}

Substitute back

u = ln (z)

= \frac{ln ^{10} ( z )}{10}

Add a constant to the solution

= \frac{ln ^{10} ( z )}{10} + C

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What is the integral of (ln^9(z))/z ?
The integral of (ln^9(z))/z is (ln^{10}(z))/(10)+C