integral of 1-(2x)/pi

Lösung

\int 1 - \frac{2 x}{π} d x

x - \frac{x ^{2}}{π} + C

Schritte zur Lösung

\int 1 - \frac{2 x}{π} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d x - \int \frac{2 x}{π} d x

\int 1 d x = x

\int \frac{2 x}{π} d x = \frac{x ^{2}}{π}

= x - \frac{x ^{2}}{π}

Füge eine Konstante zur Lösung hinzu

= x - \frac{x ^{2}}{π} + C

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