integral of 8x+1

Lösung

\int 8 x + 1 d x

4 x^{2} + x + C

Schritte zur Lösung

\int 8 x + 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 8 x d x + \int 1 d x

\int 8 x d x = 4 x^{2}

\int 1 d x = x

= 4 x^{2} + x

Füge eine Konstante zur Lösung hinzu

= 4 x^{2} + x + C

\int sec (t) (4 sec (t) + 9 tan (t)) d t

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