What is the integral of \sqrt[3]{x}+3 ?

The integral of \sqrt[3]{x}+3 is 3/4 x^{4/3}+3x+C

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integral of \sqrt[3]{x}+3

\frac{3}{4} x^{\frac{4}{3}} + 3 x + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int 3 d x = 3 x

= \frac{3}{4} x^{\frac{4}{3}} + 3 x

Add a constant to the solution

= \frac{3}{4} x^{\frac{4}{3}} + 3 x + C

What is the integral of \sqrt[3]{x}+3 ?
The integral of \sqrt[3]{x}+3 is 3/4 x^{4/3}+3x+C