What is the integral of (4x^2+7+2/(x^2+1)) ?

The integral of (4x^2+7+2/(x^2+1)) is (4x^3)/3+7x+2arctan(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (4x^2+7+2/(x^2+1))

\int (4 x^{2} + 7 + \frac{2}{x ^{2} + 1}) d x

\frac{4 x ^{3}}{3} + 7 x + 2 arctan (x) + C

Solution steps

\int 4 x^{2} + 7 + \frac{2}{x ^{2} + 1} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{2} d x + \int 7 d x + \int \frac{2}{x ^{2} + 1} d x

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

\int 7 d x = 7 x

\int \frac{2}{x ^{2} + 1} d x = 2 arctan (x)

= \frac{4 x ^{3}}{3} + 7 x + 2 arctan (x)

Add a constant to the solution

= \frac{4 x ^{3}}{3} + 7 x + 2 arctan (x) + C

What is the integral of (4x^2+7+2/(x^2+1)) ?
The integral of (4x^2+7+2/(x^2+1)) is (4x^3)/3+7x+2arctan(x)+C